WestJet WS7398 Flight Status

Current status of WS7398 is Scheduled On time Expected Depart in 7 hours, 41 minutes

WS7398 - WJA7398 WestJet Airlines (WS)
JFK New York United States
Flight JFK to CLE
CLE Cleveland United States
Scheduled On time Expected Depart in 7 hours, 41 minutes
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 20:59 10 December 2025
4 A16
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 23:02 10 December 2025
Estimated 23:02 10 December 2025
TERM B6
WS7398 Detail
  • Type: Domestic Flight
  • Code Shares: AF 3086, KL 7222, LY 4244, SK 3361, VS 3149, DL 4946
  • Flight Duration: 2 hours 3 minutes
  • Flight Distance: 682 kms / 424 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: Monday, Tuesday, Wednesday, Friday, Saturday, Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 192
  • Freight capacity: 4.6 tons
  • Passenger classes: Economy
More Detail
  • Aircraft: Canadair (Bombardier) Regional Jet 900 and Challenger 890
  • Callsign: WJA7398
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Wednesday 2025-12-10 13:18 PM
  • Current Time in Cleveland: Wednesday 2025-12-10 13:18 PM

Domestic flight WestJet WS7398 takes off from New York (JFK) United States to Cleveland (CLE) United States. It's operated by WestJet Airlines. The plane leaves John F. Kennedy International Airport at 20:59 10 December 2025 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 23:02 10 December 2025 America/New_York. The flight will last about 2 hours 3 minutes.

Similar flight route from New York (JFK) to Cleveland (CLE)

Airline Flight no Departure Arrival
El Al LY4244
El Al 		10/12/2025
20:59 		2 hours 1 minutes
23:00
Endeavor Air 9E5018
Endeavor Air 		10/12/2025
09:27 		1 hours 54 minutes
11:21
Delta DL4946
Delta 		10/12/2025
20:59 		2 hours 1 minutes
23:00
Virgin Atlantic VS3149
Virgin Atlantic 		10/12/2025
20:59 		2 hours 1 minutes
23:00
Kenya Airways KQ7115
Kenya Airways 		10/12/2025
14:59 		1 hours 53 minutes
16:58
Korean Air KE7317
Korean Air 		10/12/2025
14:59 		1 hours 59 minutes
16:58
El Al LY4246
El Al 		10/12/2025
09:27 		1 hours 53 minutes
11:21
Virgin Atlantic VS3533
Virgin Atlantic 		10/12/2025
09:27 		1 hours 5 minutes
11:21

Frequently asked questions, answered

What is the scheduled flight duration for WestJet WS7398 flight?

On average, nonstop flight takes 2 hour(s) 3 minutes, with the flight distance of 682 km (424 miles).

What is the current status of WestJet WS7398 flight?

The current status of flight WestJet WS7398 is Scheduled On time.

What type of aircraft is used for the WestJet WS7398 flight?

All WestJet WS7398 flights are operated using Canadair (Bombardier) Regional Jet 900 and Challenger 890 aircraft.

When does the flight WestJet WS7398 arrive?

Flight WestJet WS7398 arrives at 23:02.

Which terminal the flight WestJet WS7398 is arriving at?

Flight WestJet WS7398 arrives in Cleveland Hopkins International Airport at Terminal TERM.

How many WestJet WS7398 flights are operated a week?

6 flights per week. The Flight WestJet WS7398 is operated on Monday, Tuesday, Wednesday, Friday, Saturday, Sunday.