WestJet WS7398 Flight Status Today

Domestic flight WestJet WS7398 takes off from New York (JFK) United States to Cleveland (CLE) United States. It's operated by WestJet Airlines. The plane leaves John F. Kennedy International Airport at 16:00 28 February 2026 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 17:34 28 February 2026 America/New_York. The flight will last about 1 hours 34 minutes.

Current status of WS7398 is Scheduled Delayed by 1h 5m Estimated Depart in 1 hour, 11 minutes

WS7398 - WJA7398 WestJet Airlines (WS)
JFK New York United States
Flight JFK to CLE
CLE Cleveland United States
Scheduled Delayed by 1h 5m Estimated Depart in 1 hour, 11 minutes
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 16:00 28 February 2026
Estimated 17:05 28 February 2026
None 2
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 17:34 28 February 2026
Estimated 18:23 28 February 2026
S D27
WS7398 Detail
  • Type: Domestic Flight
  • Code Shares: KE 7124, KL 5561, VS 2820, DL 5466
  • Flight Duration: 1 hours 34 minutes
  • Flight Distance: 682 kms / 424 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: Monday, Tuesday, Wednesday, Friday, Saturday, Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 192
  • Freight capacity: 4.6 tons
  • Passenger classes: Economy
More Detail
  • Aircraft: Canadair (Bombardier) Regional Jet 900 and Challenger 890
  • Callsign: WJA7398
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Saturday 2026-02-28 15:54 PM
  • Current Time in Cleveland: Saturday 2026-02-28 15:54 PM

Flight routes similar to WestJet WS7398

Airline Flight no Departure Arrival
Endeavor Air 9E4946
Endeavor Air 		28/02/2026
19:35 		2 hours 1 minutes
21:36
Delta DL5018
Delta 		28/02/2026
09:50 		2 hours 14 minutes
11:43
Gulf Air GF4164
Gulf Air 		28/02/2026
14:59 		1 hours 54 minutes
16:53
Delta DL4946
Delta 		28/02/2026
19:35 		2 hours 1 minutes
21:36
British Airways BA4660
British Airways 		28/02/2026
14:59 		1 hours 54 minutes
16:53
American Airlines AA4670
American Airlines 		28/02/2026
14:59 		1 hours 54 minutes
16:53
Endeavor Air 9E5018
Endeavor Air 		28/02/2026
09:50 		1 hours 53 minutes
11:43
Delta DL4975
Delta 		28/02/2026
13:55 		1 hours 52 minutes
15:47

WestJet Flight WS7398 FAQs

What is the scheduled flight duration for WestJet WS7398 flight?

On average, nonstop flight takes 1 hour(s) 34 minutes, with the flight distance of 682 km (424 miles).

What is the current status of WestJet WS7398 flight?

The current status of flight WestJet WS7398 is Scheduled Delayed by 1h 5m.

What type of aircraft is used for the WestJet WS7398 flight?

All WestJet WS7398 flights are operated using Canadair (Bombardier) Regional Jet 900 and Challenger 890 aircraft.

When does the flight WestJet WS7398 arrive?

Flight WestJet WS7398 arrives at 17:34.

Which terminal the flight WestJet WS7398 is arriving at?

Flight WestJet WS7398 arrives in Cleveland Hopkins International Airport at Terminal S.

How many WestJet WS7398 flights are operated a week?

6 flights per week. The Flight WestJet WS7398 is operated on Monday, Tuesday, Wednesday, Friday, Saturday, Sunday.