WestJet WS7398 Flight Status Today

Domestic flight WestJet WS7398 takes off from New York (JFK) United States to Cleveland (CLE) United States. It's operated by WestJet Airlines. The plane leaves John F. Kennedy International Airport at 21:05 18 January 2026 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 23:08 18 January 2026 America/New_York. The flight will last about 2 hours 3 minutes.

Current status of WS7398 is Scheduled On time Expected Depart in 11 hours, 56 minutes

WS7398 - WJA7398 WestJet Airlines (WS)
JFK New York United States
Flight JFK to CLE
CLE Cleveland United States
Scheduled On time Expected Depart in 11 hours, 56 minutes
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 21:05 18 January 2026
4 A21
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 23:08 18 January 2026
TERM B6
WS7398 Detail
  • Type: Domestic Flight
  • Code Shares: AF 3086, KL 7222, LY 4244, MU 8697, SK 3361, VS 3149, DL 4946
  • Flight Duration: 2 hours 3 minutes
  • Flight Distance: 682 kms / 424 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: Monday, Tuesday, Wednesday, Friday, Saturday, Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 192
  • Freight capacity: 4.6 tons
  • Passenger classes: Economy
More Detail
  • Aircraft: Canadair (Bombardier) Regional Jet 900 and Challenger 890
  • Callsign: WJA7398
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Sunday 2026-01-18 09:09 AM
  • Current Time in Cleveland: Sunday 2026-01-18 09:09 AM

Flight routes similar to WestJet WS7398

Airline Flight no Departure Arrival
Virgin Atlantic VS3533
Virgin Atlantic 		18/01/2026
09:54 		1 hours 55 minutes
11:49
Endeavor Air 9E4975
Endeavor Air 		18/01/2026
14:28 		1 hours 54 minutes
16:22
Saudia Airlines SV6985
Saudia Airlines 		18/01/2026
14:28 		1 hours 54 minutes
16:22
Delta DL5018
Delta 		18/01/2026
09:54 		1 hours 55 minutes
11:49
Delta DL4975
Delta 		18/01/2026
14:28 		1 hours 54 minutes
16:22
Endeavor Air 9E4946
Endeavor Air 		18/01/2026
21:05 		2 hours 3 minutes
23:08
Korean Air KE7317
Korean Air 		18/01/2026
13:55 		2 hours 46 minutes
15:49
Virgin Atlantic VS2911
Virgin Atlantic 		18/01/2026
13:55 		2 hours 46 minutes
15:49

WestJet Flight WS7398 FAQs

What is the scheduled flight duration for WestJet WS7398 flight?

On average, nonstop flight takes 2 hour(s) 3 minutes, with the flight distance of 682 km (424 miles).

What is the current status of WestJet WS7398 flight?

The current status of flight WestJet WS7398 is Scheduled On time.

What type of aircraft is used for the WestJet WS7398 flight?

All WestJet WS7398 flights are operated using Canadair (Bombardier) Regional Jet 900 and Challenger 890 aircraft.

When does the flight WestJet WS7398 arrive?

Flight WestJet WS7398 arrives at 23:08.

Which terminal the flight WestJet WS7398 is arriving at?

Flight WestJet WS7398 arrives in Cleveland Hopkins International Airport at Terminal TERM.

How many WestJet WS7398 flights are operated a week?

6 flights per week. The Flight WestJet WS7398 is operated on Monday, Tuesday, Wednesday, Friday, Saturday, Sunday.