JetBlue Airways B61341 Flight Status Today

Domestic flight JetBlue Airways B61341 takes off from Boston (BOS) United States to Cleveland (CLE) United States. It's operated by JetBlue Airways. The plane leaves Logan International Airport at 18:20 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 20:47 America/New_York. The flight will last about 2 hours 27 minutes.

B61341 - JBU1341 JetBlue Airways (B6)
BOS Boston United States
Flight BOS to CLE
CLE Cleveland United States
Contact Airlines It may not operate on the date requested
Departure Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 18:20
C C28
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 20:47
TERM None
B61341 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 27 minutes
  • Flight Distance: 903 kms / 561 miles
Airline
  • JetBlue Airways
  • IATA: B6
  • ICAO: JBU
  • Operating Days: Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A220-300 Passenger
  • Callsign: F-KTPA2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Boston: Monday 2025-12-29 11:09 AM
  • Current Time in Cleveland: Monday 2025-12-29 11:09 AM

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JetBlue Airways Flight B61341 FAQs

What is the scheduled flight duration for JetBlue Airways B61341 flight?

On average, nonstop flight takes 2 hour(s) 27 minutes, with the flight distance of 903 km (561 miles).

What type of aircraft is used for the JetBlue Airways B61341 flight?

All JetBlue Airways B61341 flights are operated using Airbus A220-300 Passenger aircraft.

Which terminal the flight JetBlue Airways B61341 is arriving at?

Flight JetBlue Airways B61341 arrives in Cleveland Hopkins International Airport at Terminal TERM.

How many JetBlue Airways B61341 flights are operated a week?

1 flights per week. The Flight JetBlue Airways B61341 is operated on Sunday.