Delta DL5674 Flight Status Today

Domestic flight Delta DL5674 takes off from Boston (BOS) United States to Cleveland (CLE) United States. It's operated by Delta Airlines. The plane leaves Logan International Airport at 08:38 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 10:48 America/New_York. The flight will last about 2 hours 10 minutes.

DL5674 - DAL5674 Delta Airlines (DL)
BOS Boston United States
Flight BOS to CLE
CLE Cleveland United States
Contact Airlines It may not operate on the date requested
Departure Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 08:38
A A7
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 10:48
TERM None
DL5674 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 10 minutes
  • Flight Distance: 903 kms / 561 miles
Airline
  • Delta Airlines
  • IATA: DL
  • ICAO: DAL
  • Operating Days: Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 175
  • Callsign: T-KLGA56
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Boston: Saturday 2026-05-02 11:15 AM
  • Current Time in Cleveland: Saturday 2026-05-02 11:15 AM

Flight routes similar to Delta DL5674

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Korean Air KE3301
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Republic Airlines YX5655
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LATAM Airlines LA6749
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Delta Flight DL5674 FAQs

What is the scheduled flight duration for Delta DL5674 flight?

On average, nonstop flight takes 2 hour(s) 10 minutes, with the flight distance of 903 km (561 miles).

What type of aircraft is used for the Delta DL5674 flight?

All Delta DL5674 flights are operated using Embraer 175 aircraft.

Which terminal the flight Delta DL5674 is arriving at?

Flight Delta DL5674 arrives in Cleveland Hopkins International Airport at Terminal TERM.

How many Delta DL5674 flights are operated a week?

1 flights per week. The Flight Delta DL5674 is operated on Sunday.