Aeromexico AM5512 Flight Status Today

Domestic flight Aeromexico AM5512 takes off from Fayetteville (FAY) United States to Atlanta (ATL) United States. It's operated by Aeromexico. The plane leaves Fayetteville Regional Airport at 12:42 America/New_York. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 14:19 America/New_York. The flight will last about 1 hours 51 minutes.

AM5512 - AMX5512 Aeromexico (AM)
FAY Fayetteville United States
Flight FAY to ATL
ATL Atlanta United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 24-November-2019
Departure Fayetteville Regional Airport
IATA: FAYICAO: KFAY
Scheduled 12:42
3
Arrival Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 14:19
S D28
AM5512 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 51 minutes
  • Flight Distance: 533 kms / 331 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 50
  • Freight capacity: 1.5 tons
  • Passenger classes: Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: E75L
  • Callsign: AMX5512
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Fayetteville: Sunday 2026-05-03 03:56 AM
  • Current Time in Atlanta: Sunday 2026-05-03 03:56 AM

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Aeromexico Flight AM5512 FAQs

What is the scheduled flight duration for Aeromexico AM5512 flight?

On average, nonstop flight takes 1 hour(s) 51 minutes, with the flight distance of 533 km (331 miles).

What type of aircraft is used for the Aeromexico AM5512 flight?

All Aeromexico AM5512 flights are operated using E75L aircraft.

Which terminal the flight Aeromexico AM5512 is arriving at?

Flight Aeromexico AM5512 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal S.