Air Canada AC7479 Flight Status Today

International flight Air Canada AC7479 takes off from Newark (EWR) United States to Toronto (YYZ) Canada. It's operated by Air Canada. The plane leaves Newark Liberty International Airport at 16:35 America/New_York. The flight is expected to land at Pearson International Airport at 18:10 America/Toronto. The flight will last about 1 hours 35 minutes.

AC7479 - ACA7479 Air Canada (AC)
EWR Newark United States
Flight EWR to YYZ
YYZ Toronto Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 30-April-2022
Departure Newark Liberty International Airport
IATA: EWRICAO: KEWR
Scheduled 16:35
A None
Arrival Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled 18:10
1 None
AC7479 Detail
  • Type: International Flight
  • Flight Duration: 1 hours 35 minutes
  • Flight Distance: 558 kms / 347 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 73
  • Freight capacity: 1.2 tons
  • Passenger classes: First Class, Economy, Business Class, Shuttle
More Detail
  • Aircraft: Embraer 175
  • Callsign: ACA7479
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Toronto
  • Current Time in Newark: Monday 2026-01-19 03:26 AM
  • Current Time in Toronto: Monday 2026-01-19 03:26 AM

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Air Canada Flight AC7479 FAQs

What is the scheduled flight duration for Air Canada AC7479 flight?

On average, nonstop flight takes 1 hour(s) 35 minutes, with the flight distance of 558 km (347 miles).

What type of aircraft is used for the Air Canada AC7479 flight?

All Air Canada AC7479 flights are operated using Embraer 175 aircraft.

Which terminal the flight Air Canada AC7479 is arriving at?

Flight Air Canada AC7479 arrives in Pearson International Airport at Terminal 1.