Air Canada AC7475 Flight Status Today

International flight Air Canada AC7475 takes off from Newark (EWR) United States to Toronto (YYZ) Canada. It's operated by Air Canada. The plane leaves Newark Liberty International Airport at 11:15 America/New_York. The flight is expected to land at Pearson International Airport at 12:50 America/Toronto. The flight will last about 1 hours 33 minutes.

AC7475 - ACA7475 Air Canada (AC)
EWR Newark United States
Flight EWR to YYZ
YYZ Toronto Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 30-April-2022
Departure Newark Liberty International Airport
IATA: EWRICAO: KEWR
Scheduled 11:15
A None
Arrival Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled 12:50
1 None
AC7475 Detail
  • Type: International Flight
  • Flight Duration: 1 hours 33 minutes
  • Flight Distance: 558 kms / 347 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 73
  • Freight capacity: 1.2 tons
  • Passenger classes: First Class, Economy, Business Class, Shuttle
More Detail
  • Aircraft: Embraer 175
  • Callsign: ACA7475
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Toronto
  • Current Time in Newark: Tuesday 2026-03-24 03:42 AM
  • Current Time in Toronto: Tuesday 2026-03-24 03:42 AM

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Air Canada Flight AC7475 FAQs

What is the scheduled flight duration for Air Canada AC7475 flight?

On average, nonstop flight takes 1 hour(s) 33 minutes, with the flight distance of 558 km (347 miles).

What type of aircraft is used for the Air Canada AC7475 flight?

All Air Canada AC7475 flights are operated using Embraer 175 aircraft.

Which terminal the flight Air Canada AC7475 is arriving at?

Flight Air Canada AC7475 arrives in Pearson International Airport at Terminal 1.