Air Canada AC2398 Flight Status Today

Domestic flight Air Canada AC2398 takes off from Kelowna (YLW) Canada to Toronto (YYZ) Canada. It's operated by Air Canada. The plane leaves Kelowna International Airport at 23:25 America/Vancouver. The flight is expected to land at Pearson International Airport at 06:49 America/Toronto. The flight will last about 2 hours 38 minutes.

AC2398 - ACA2398 Air Canada (AC)
YLW Kelowna Canada
Flight YLW to YYZ
YYZ Toronto Canada
Contact Airlines It may not operate on the date requested
Departure Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 23:25
None None
Arrival Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled 06:49
None None
AC2398 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 38 minutes
  • Flight Distance: 3075 kms / 1911 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days:
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737 MAX 8
  • Callsign: ACA2398
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Toronto
  • Current Time in Kelowna: Saturday 2026-03-21 01:19 AM
  • Current Time in Toronto: Saturday 2026-03-21 04:19 AM

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Air Canada Flight AC2398 FAQs

What is the scheduled flight duration for Air Canada AC2398 flight?

On average, nonstop flight takes 2 hour(s) 38 minutes, with the flight distance of 3075 km (1911 miles).

What type of aircraft is used for the Air Canada AC2398 flight?

All Air Canada AC2398 flights are operated using Boeing 737 MAX 8 aircraft.