Air Canada AC1998 Flight Status Today

Domestic flight Air Canada AC1998 takes off from Kelowna (YLW) Canada to Toronto (YYZ) Canada. It's operated by Air Canada. The plane leaves Kelowna International Airport at 23:25 America/Vancouver. The flight is expected to land at Pearson International Airport at 06:49 America/Toronto. The flight will last about 4 hours 24 minutes.

AC1998 - ACA1998 Air Canada (AC)
YLW Kelowna Canada
Flight YLW to YYZ
YYZ Toronto Canada
Contact Airlines It may not operate on the date requested
Departure Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 23:25
None 8
Arrival Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled 06:49
1 D51
AC1998 Detail
  • Type: Domestic Flight
  • Flight Duration: 4 hours 24 minutes
  • Flight Distance: 3075 kms / 1911 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: Wednesday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: None
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Toronto
  • Current Time in Kelowna: Wednesday 2026-04-15 06:30 AM
  • Current Time in Toronto: Wednesday 2026-04-15 09:30 AM

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Air Canada Flight AC1998 FAQs

What is the scheduled flight duration for Air Canada AC1998 flight?

On average, nonstop flight takes 4 hour(s) 24 minutes, with the flight distance of 3075 km (1911 miles).

What type of aircraft is used for the Air Canada AC1998 flight?

All Air Canada AC1998 flights are operated using Airbus A320 aircraft.

Which terminal the flight Air Canada AC1998 is arriving at?

Flight Air Canada AC1998 arrives in Pearson International Airport at Terminal 1.

How many Air Canada AC1998 flights are operated a week?

1 flights per week. The Flight Air Canada AC1998 is operated on Wednesday.