Air Canada AC1912 Flight Status Today

Domestic flight Air Canada AC1912 takes off from Kelowna (YLW) Canada to Toronto (YYZ) Canada. It's operated by Air Canada. The plane leaves Kelowna International Airport at 23:20 America/Vancouver. The flight is expected to land at Pearson International Airport at 06:44 America/Toronto. The flight will last about 4 hours 24 minutes.

AC1912 - ACA1912 Air Canada (AC)
YLW Kelowna Canada
Flight YLW to YYZ
YYZ Toronto Canada
Contact Airlines It may not operate on the date requested
Departure Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 23:20
None 6
Arrival Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled 06:44
1 D41
AC1912 Detail
  • Type: Domestic Flight
  • Flight Duration: 4 hours 24 minutes
  • Flight Distance: 3075 kms / 1911 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: Monday
Passenger Services
  • Service type: Normal passenger
  • Seats: 208
  • Freight capacity: 14.4 tons
  • Passenger classes: Economy, Shuttle
More Detail
  • Aircraft: Airbus A319
  • Callsign: ROU1912
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Toronto
  • Current Time in Kelowna: Monday 2025-12-29 08:55 AM
  • Current Time in Toronto: Monday 2025-12-29 11:55 AM

Flight routes similar to Air Canada AC1912

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Aeromexico AM7067
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Air Canada Flight AC1912 FAQs

What is the scheduled flight duration for Air Canada AC1912 flight?

On average, nonstop flight takes 4 hour(s) 24 minutes, with the flight distance of 3075 km (1911 miles).

What type of aircraft is used for the Air Canada AC1912 flight?

All Air Canada AC1912 flights are operated using Airbus A319 aircraft.

Which terminal the flight Air Canada AC1912 is arriving at?

Flight Air Canada AC1912 arrives in Pearson International Airport at Terminal 1.

How many Air Canada AC1912 flights are operated a week?

1 flights per week. The Flight Air Canada AC1912 is operated on Monday.