Air Canada AC1910 Flight Status Today

Domestic flight Air Canada AC1910 takes off from Kelowna (YLW) Canada to Toronto (YYZ) Canada. It's operated by Air Canada. The plane leaves Kelowna International Airport at 12:00 America/Vancouver. The flight is expected to land at Pearson International Airport at 19:24 America/Toronto. The flight will last about 3 hours 42 minutes.

AC1910 - ACA1910 Air Canada (AC)
YLW Kelowna Canada
Flight YLW to YYZ
YYZ Toronto Canada
Contact Airlines It may not operate on the date requested
Departure Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 12:00
None 9
Arrival Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled 19:24
1 D45
AC1910 Detail
  • Type: Domestic Flight
  • Flight Duration: 3 hours 42 minutes
  • Flight Distance: 3075 kms / 1911 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: Tuesday
Passenger Services
  • Service type: Normal passenger
  • Seats: 208
  • Freight capacity: 14.4 tons
  • Passenger classes: Economy, Shuttle
More Detail
  • Aircraft: Airbus A321 (sharklets)
  • Callsign: ROU1910
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Toronto
  • Current Time in Kelowna: Friday 2026-05-01 02:13 AM
  • Current Time in Toronto: Friday 2026-05-01 05:13 AM

Flight routes similar to Air Canada AC1910

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WestJet WS770
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Air Canada Flight AC1910 FAQs

What is the scheduled flight duration for Air Canada AC1910 flight?

On average, nonstop flight takes 3 hour(s) 42 minutes, with the flight distance of 3075 km (1911 miles).

What type of aircraft is used for the Air Canada AC1910 flight?

All Air Canada AC1910 flights are operated using Airbus A321 (sharklets) aircraft.

Which terminal the flight Air Canada AC1910 is arriving at?

Flight Air Canada AC1910 arrives in Pearson International Airport at Terminal 1.

How many Air Canada AC1910 flights are operated a week?

1 flights per week. The Flight Air Canada AC1910 is operated on Tuesday.