American Airlines AA4808 Flight Status Today

Domestic flight American Airlines AA4808 takes off from Columbus (CMH) United States to New York (JFK) United States. It's operated by American Airlines. The plane leaves John Glenn Columbus International Airport at 06:06 27 February 2026 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 07:59 27 February 2026 America/New_York. The flight will last about 1 hours 55 minutes.

Current status of AA4808 is Arrived On time

AA4808 - AAL4808 American Airlines (AA)
CMH Columbus United States
Flight CMH to JFK
JFK New York United States
Arrived On time
Departure John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled 06:06 27 February 2026
Actual 06:03 27 February 2026
None B21
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 07:59 27 February 2026
Actual 07:58 27 February 2026
8 39
AA4808 Detail
  • Type: Domestic Flight
  • Code Shares: BA 6616, CX 7553, JL 7806, QR 9283
  • Flight Duration: 1 hours 55 minutes
  • Flight Distance: 776 kms / 482 miles
Airline
  • American Airlines
  • IATA: AA
  • ICAO: AAL
  • Operating Days: Thursday
Passenger Services
  • Service type: Normal passenger
  • Seats: 50
  • Freight capacity: 0 tons
  • Passenger classes: Economy
More Detail
  • Aircraft: Embraer 175
  • Callsign: F-KTEB2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Columbus: Friday 2026-02-27 23:10 PM
  • Current Time in New York: Friday 2026-02-27 23:10 PM

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American Airlines Flight AA4808 FAQs

What is the scheduled flight duration for American Airlines AA4808 flight?

On average, nonstop flight takes 1 hour(s) 55 minutes, with the flight distance of 776 km (482 miles).

What is the current status of American Airlines AA4808 flight?

The current status of flight American Airlines AA4808 is Arrived On time.

What type of aircraft is used for the American Airlines AA4808 flight?

All American Airlines AA4808 flights are operated using Embraer 175 aircraft.

When does the flight American Airlines AA4808 arrive?

Flight American Airlines AA4808 arrives at 07:59.

Which terminal the flight American Airlines AA4808 is arriving at?

Flight American Airlines AA4808 arrives in John F. Kennedy International Airport at Terminal 8.

How many American Airlines AA4808 flights are operated a week?

1 flights per week. The Flight American Airlines AA4808 is operated on Thursday.