Republic Airlines YX4808 Flight Status Today

Domestic flight Republic Airlines YX4808 takes off from Columbus (CMH) United States to New York (JFK) United States. It's operated by Republic Airlines. The plane leaves John Glenn Columbus International Airport at 06:25 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 08:28 America/New_York. The flight will last about 1 hours 50 minutes.

YX4808 - RPA4808 Republic Airlines (YX)
CMH Columbus United States
Flight CMH to JFK
JFK New York United States
Contact Airlines It may not operate on the date requested
Departure John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled 06:25
None B26
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 08:28
8 44
YX4808 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 50 minutes
  • Flight Distance: 776 kms / 482 miles
Airline
  • Republic Airlines
  • IATA: YX
  • ICAO: RPA
  • Operating Days: Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 175
  • Callsign: RPA4808
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Columbus: Thursday 2026-01-01 00:26 AM
  • Current Time in New York: Thursday 2026-01-01 00:26 AM

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Republic Airlines Flight YX4808 FAQs

What is the scheduled flight duration for Republic Airlines YX4808 flight?

On average, nonstop flight takes 1 hour(s) 50 minutes, with the flight distance of 776 km (482 miles).

What type of aircraft is used for the Republic Airlines YX4808 flight?

All Republic Airlines YX4808 flights are operated using Embraer 175 aircraft.

Which terminal the flight Republic Airlines YX4808 is arriving at?

Flight Republic Airlines YX4808 arrives in John F. Kennedy International Airport at Terminal 8.

How many Republic Airlines YX4808 flights are operated a week?

1 flights per week. The Flight Republic Airlines YX4808 is operated on Sunday.