Republic Airlines YX4607 Flight Status Today

Domestic flight Republic Airlines YX4607 takes off from Cleveland (CLE) United States to New York (JFK) United States. It's operated by Republic Airlines. The plane leaves Cleveland Hopkins International Airport at 19:10 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 20:58 America/New_York. The flight will last about 1 hours 48 minutes.

YX4607 - RPA4607 Republic Airlines (YX)
CLE Cleveland United States
Flight CLE to JFK
JFK New York United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 19:10
None C5
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 20:58
8 39
YX4607 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 48 minutes
  • Flight Distance: 682 kms / 424 miles
Airline
  • Republic Airlines
  • IATA: YX
  • ICAO: RPA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 175
  • Callsign: RPA4607
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Monday 2026-03-23 02:09 AM
  • Current Time in New York: Monday 2026-03-23 02:09 AM

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Republic Airlines Flight YX4607 FAQs

What is the scheduled flight duration for Republic Airlines YX4607 flight?

On average, nonstop flight takes 1 hour(s) 48 minutes, with the flight distance of 682 km (424 miles).

What type of aircraft is used for the Republic Airlines YX4607 flight?

All Republic Airlines YX4607 flights are operated using Embraer 175 aircraft.

Which terminal the flight Republic Airlines YX4607 is arriving at?

Flight Republic Airlines YX4607 arrives in John F. Kennedy International Airport at Terminal 8.