AeroItalia XZ4498 Flight Status Today

Domestic flight AeroItalia XZ4498 takes off from Milan (MXP) Italy to Rome (FCO) Italy. It's operated by AeroItalia. The plane leaves Milano Malpensa Airport at 22:04 Europe/Rome. The flight is expected to land at Leonardo da Vinci-Fiumicino Airport at None Europe/Rome. The flight will last about 48 minutes.

XZ4498 - AEZ4498 AeroItalia (XZ)
MXP Milan Italy
Flight MXP to FCO
FCO Rome Italy
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Milano Malpensa Airport
IATA: MXPICAO: LIMC
Scheduled 22:04
None None
Arrival Leonardo da Vinci-Fiumicino Airport
IATA: FCOICAO: LIRF
Scheduled None
None None
XZ4498 Detail
  • Type: Domestic Flight
  • Flight Duration: 48 minutes
  • Flight Distance: 512 kms / 318 miles
Airline
  • AeroItalia
  • IATA: XZ
  • ICAO: AEZ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-86Q
  • Callsign: AEZ4498
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: Europe/Rome
  • Current Time in Milan: Monday 2025-12-29 17:40 PM
  • Current Time in Rome: Monday 2025-12-29 17:40 PM

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AeroItalia Flight XZ4498 FAQs

What is the scheduled flight duration for AeroItalia XZ4498 flight?

On average, nonstop flight takes 48 minutes, with the flight distance of 512 km (318 miles).

What type of aircraft is used for the AeroItalia XZ4498 flight?

All AeroItalia XZ4498 flights are operated using Boeing 737-86Q aircraft.