JetSuiteX XE8273 Flight Status Today

Domestic flight JetSuiteX XE8273 takes off from Los Angeles (VNY) United States to Waco (ACT) United States. It's operated by JSX. The plane leaves Van Nuys Airport at 12:00 America/Los_Angeles. The flight is expected to land at Waco Municipal Airport at 16:27 America/Chicago. The flight will last about 1 hours 28 minutes.

XE8273 - JSX8273 JSX (XE)
VNY Los Angeles United States
Flight VNY to ACT
ACT Waco United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 02-April-2021
Departure Van Nuys Airport
IATA: VNYICAO: KVNY
Scheduled 12:00
None None
Arrival Waco Municipal Airport
IATA: ACTICAO: KACT
Scheduled 16:27
None None
XE8273 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 28 minutes
  • Flight Distance: 2007 kms / 1247 miles
Airline
  • JSX
  • IATA: XE
  • ICAO: JSX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: E135
  • Callsign: JSX8273
  • Departure Timezone: America/Los_Angeles
  • Arrival Timezone: America/Chicago
  • Current Time in Los Angeles: Monday 2026-01-19 20:51 PM
  • Current Time in Waco: Monday 2026-01-19 22:51 PM

Flight routes similar to JetSuiteX XE8273

Airline Flight no Departure Arrival
JetSuiteX XE8220
JetSuiteX 		19/01/2026
12:00 		1 hours 25 minutes
16:22

JetSuiteX Flight XE8273 FAQs

What is the scheduled flight duration for JetSuiteX XE8273 flight?

On average, nonstop flight takes 1 hour(s) 28 minutes, with the flight distance of 2007 km (1247 miles).

What type of aircraft is used for the JetSuiteX XE8273 flight?

All JetSuiteX XE8273 flights are operated using E135 aircraft.