JetSuiteX XE4968 Flight Status Today

Domestic flight JetSuiteX XE4968 takes off from Buffalo (BUF) United States to Newark (EWR) United States. It's operated by JSX. The plane leaves Buffalo Niagara International Airport at 08:21 America/New_York. The flight is expected to land at Newark Liberty International Airport at None America/New_York. The flight will last about 59 minutes.

XE4968 - JSX4968 JSX (XE)
BUF Buffalo United States
Flight BUF to EWR
EWR Newark United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Buffalo Niagara International Airport
IATA: BUFICAO: KBUF
Scheduled 08:21
None None
Arrival Newark Liberty International Airport
IATA: EWRICAO: KEWR
Scheduled None
None None
XE4968 Detail
  • Type: Domestic Flight
  • Flight Duration: 59 minutes
  • Flight Distance: 453 kms / 281 miles
Airline
  • JSX
  • IATA: XE
  • ICAO: JSX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer ERJ-145LR
  • Callsign: UCA4968
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Buffalo: Saturday 2026-02-07 18:09 PM
  • Current Time in Newark: Saturday 2026-02-07 18:09 PM

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JetSuiteX Flight XE4968 FAQs

What is the scheduled flight duration for JetSuiteX XE4968 flight?

On average, nonstop flight takes 59 minutes, with the flight distance of 453 km (281 miles).

What type of aircraft is used for the JetSuiteX XE4968 flight?

All JetSuiteX XE4968 flights are operated using Embraer ERJ-145LR aircraft.