JetSuiteX XE4953 Flight Status Today

Domestic flight JetSuiteX XE4953 takes off from Houston (IAH) United States to Knoxville (TYS) United States. It's operated by JSX. The plane leaves George Bush Intercontinental Airport at 11:20 America/Chicago. The flight is expected to land at McGhee Tyson Airport at None America/New_York. The flight will last about 1 hours 42 minutes.

XE4953 - JSX4953 JSX (XE)
IAH Houston United States
Flight IAH to TYS
TYS Knoxville United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure George Bush Intercontinental Airport
IATA: IAHICAO: KIAH
Scheduled 11:20
None None
Arrival McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled None
None None
XE4953 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 42 minutes
  • Flight Distance: 1242 kms / 771 miles
Airline
  • JSX
  • IATA: XE
  • ICAO: JSX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer ERJ-145LR
  • Callsign: UCA4953
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/New_York
  • Current Time in Houston: Friday 2026-01-23 18:01 PM
  • Current Time in Knoxville: Friday 2026-01-23 19:01 PM

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JetSuiteX Flight XE4953 FAQs

What is the scheduled flight duration for JetSuiteX XE4953 flight?

On average, nonstop flight takes 1 hour(s) 42 minutes, with the flight distance of 1242 km (771 miles).

What type of aircraft is used for the JetSuiteX XE4953 flight?

All JetSuiteX XE4953 flights are operated using Embraer ERJ-145LR aircraft.