JetSuiteX XE4273 Flight Status Today

Domestic flight JetSuiteX XE4273 takes off from Houston (IAH) United States to Oklahoma City (OKC) United States. It's operated by JSX. The plane leaves George Bush Intercontinental Airport at 09:07 America/Chicago. The flight is expected to land at Will Rogers World Airport at None America/Chicago. The flight will last about 1 hours 5 minutes.

XE4273 - JSX4273 JSX (XE)
IAH Houston United States
Flight IAH to OKC
OKC Oklahoma City United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure George Bush Intercontinental Airport
IATA: IAHICAO: KIAH
Scheduled 09:07
None None
Arrival Will Rogers World Airport
IATA: OKCICAO: KOKC
Scheduled None
None None
XE4273 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 5 minutes
  • Flight Distance: 636 kms / 395 miles
Airline
  • JSX
  • IATA: XE
  • ICAO: JSX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer ERJ-145LR
  • Callsign: UCA4273
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Chicago
  • Current Time in Houston: Sunday 2026-05-03 19:50 PM
  • Current Time in Oklahoma City: Sunday 2026-05-03 19:50 PM

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JetSuiteX Flight XE4273 FAQs

What is the scheduled flight duration for JetSuiteX XE4273 flight?

On average, nonstop flight takes 1 hour(s) 5 minutes, with the flight distance of 636 km (395 miles).

What type of aircraft is used for the JetSuiteX XE4273 flight?

All JetSuiteX XE4273 flights are operated using Embraer ERJ-145LR aircraft.