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ARINC XA9945 flight status now
XA9945 - XAA9945
ARINC (XA)
CMH
Columbus United States
TEB
Teterboro United States
Contact Airlines
It may not operate on the date requested
XA9945 Detail
- Type: Domestic Flight
- Flight Duration:
- Flight Distance: 754 kms / 469 miles
Airline
- ARINC
- IATA: XA
- ICAO: XAA
- Operating Days: Wednesday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: None
- Callsign: None
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Columbus: Tuesday 2025-11-18 14:52 PM
- Current Time in Teterboro: Tuesday 2025-11-18 14:52 PM
Domestic flight ARINC XA9945 takes off from Columbus (CMH) United States to Teterboro (TEB) United States. It's operated by ARINC. The plane leaves John Glenn Columbus International Airport at None America/New_York. The flight is expected to land at Teterboro Airport at 18:10 America/New_York. The flight will last about .
Similar flight route from Columbus (CMH) to Teterboro (TEB)
Frequently asked questions, answered
How long is the flight from Columbus to Teterboro?
On average, nonstop flight takes , with the flight distance of 754 km (469 miles).
How many ARINC XA9945 flights are operated a week?
1 flights per week. The Flight ARINC XA9945 is operated on Wednesday.
