ARINC XA7499 Flight Status Today

Domestic flight ARINC XA7499 takes off from Teterboro (TEB) United States to Columbus (CMH) United States. It's operated by ARINC. The plane leaves Teterboro Airport at 17:30 America/New_York. The flight is expected to land at John Glenn Columbus International Airport at None America/New_York. The flight will last about .

XA7499 - XAA7499 ARINC (XA)
TEB Teterboro United States
Flight TEB to CMH
CMH Columbus United States
Contact Airlines It may not operate on the date requested
Departure Teterboro Airport
IATA: TEBICAO: KTEB
Scheduled 17:30
Arrival John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled None
XA7499 Detail
  • Type: Domestic Flight
  • Flight Duration:
  • Flight Distance: 754 kms / 469 miles
Airline
  • ARINC
  • IATA: XA
  • ICAO: XAA
  • Operating Days: Tuesday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Teterboro: Wednesday 2025-12-31 04:56 AM
  • Current Time in Columbus: Wednesday 2025-12-31 04:56 AM

Flight routes similar to ARINC XA7499

Airline Flight no Departure Arrival
Kalitta Air K413
Kalitta Air 		31/12/2025
09:10 		1 hours 2 minutes
10:32
ARINC XA8525
ARINC 		31/12/2025
09:15
None
ARINC XA8907
ARINC 		31/12/2025
17:30
None
ARINC XA3808
ARINC 		31/12/2025
14:15
None

ARINC Flight XA7499 FAQs

What is the scheduled flight duration for ARINC XA7499 flight?

On average, nonstop flight takes , with the flight distance of 754 km (469 miles).

How many ARINC XA7499 flights are operated a week?

1 flights per week. The Flight ARINC XA7499 is operated on Tuesday.