ARINC XA7499 flight status now

XA7499 - XAA7499 ARINC (XA)
TEB Teterboro United States
Flight TEB to CMH
CMH Columbus United States
Contact Airlines It may not operate on the date requested
Departure Teterboro Airport
IATA: TEBICAO: KTEB
Scheduled 17:30
Arrival John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled None
XA7499 Detail
  • Type: Domestic Flight
  • Flight Duration:
  • Flight Distance: 754 kms / 469 miles
Airline
  • ARINC
  • IATA: XA
  • ICAO: XAA
  • Operating Days: Tuesday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Teterboro: Tuesday 2025-11-18 19:32 PM
  • Current Time in Columbus: Tuesday 2025-11-18 19:32 PM

Domestic flight ARINC XA7499 takes off from Teterboro (TEB) United States to Columbus (CMH) United States. It's operated by ARINC. The plane leaves Teterboro Airport at 17:30 America/New_York. The flight is expected to land at John Glenn Columbus International Airport at None America/New_York. The flight will last about .

Similar flight route from Teterboro (TEB) to Columbus (CMH)

Airline Flight no Departure Arrival
Kalitta Air K413
Kalitta Air 		18/11/2025
09:10 		1 hours 2 minutes
10:32
ARINC XA8525
ARINC 		18/11/2025
09:15
None
ARINC XA8907
ARINC 		18/11/2025
17:30
None
ARINC XA3808
ARINC 		18/11/2025
14:15
None

Frequently asked questions, answered

How long is the flight from Teterboro to Columbus?

On average, nonstop flight takes , with the flight distance of 754 km (469 miles).

How many ARINC XA7499 flights are operated a week?

1 flights per week. The Flight ARINC XA7499 is operated on Tuesday.