WestJet WS9988 Flight Status Today

Domestic flight WestJet WS9988 takes off from Kelowna (YLW) Canada to Calgary (YYC) Canada. It's operated by WestJet Airlines. The plane leaves Kelowna International Airport at 00:15 America/Vancouver. The flight is expected to land at Calgary International Airport at 02:07 America/Edmonton. The flight will last about 50 minutes.

WS9988 - WJA9988 WestJet Airlines (WS)
YLW Kelowna Canada
Flight YLW to YYC
YYC Calgary Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 28-December-2021
Departure Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 00:15
None None
Arrival Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 02:07
None None
WS9988 Detail
  • Type: Domestic Flight
  • Flight Duration: 50 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Edmonton
  • Current Time in Kelowna: Wednesday 2026-04-29 23:59 PM
  • Current Time in Calgary: Thursday 2026-04-30 00:59 AM

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WestJet Flight WS9988 FAQs

What is the scheduled flight duration for WestJet WS9988 flight?

On average, nonstop flight takes 50 minutes, with the flight distance of 403 km (250 miles).