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WestJet WS9988 Flight Status Today
Domestic flight WestJet WS9988 takes off from Kelowna (YLW) Canada to Calgary (YYC) Canada. It's operated by WestJet Airlines. The plane leaves Kelowna International Airport at 00:15 America/Vancouver. The flight is expected to land at Calgary International Airport at 02:07 America/Edmonton. The flight will last about 50 minutes.
WS9988 - WJA9988
WestJet Airlines (WS)
YLW
Kelowna Canada
YYC
Calgary Canada
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on 28-December-2021
WS9988 Detail
- Type: Domestic Flight
- Flight Duration: 50 minutes
- Flight Distance: 403 kms / 250 miles
Airline
- WestJet Airlines
- IATA: WS
- ICAO: WJA
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: None
- Callsign: None
- Departure Timezone: America/Vancouver
- Arrival Timezone: America/Edmonton
- Current Time in Kelowna: Sunday 2026-01-18 18:49 PM
- Current Time in Calgary: Sunday 2026-01-18 19:49 PM
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QF3406 Qantas |
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|
UA8034 United Airlines |
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|
|
WS184 WestJet |
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WS3608 WestJet |
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WestJet Flight WS9988 FAQs
What is the scheduled flight duration for WestJet WS9988 flight?
On average, nonstop flight takes 50 minutes, with the flight distance of 403 km (250 miles).