WestJet WS958 Flight Status Today

Domestic flight WestJet WS958 takes off from Kelowna (YLW) Canada to Calgary (YYC) Canada. It's operated by WestJet Airlines. The plane leaves Kelowna International Airport at 10:25 America/Vancouver. The flight is expected to land at Calgary International Airport at 12:28 America/Edmonton. The flight will last about 1 hours 10 minutes.

WS958 - WJA958 WestJet Airlines (WS)
YLW Kelowna Canada
Flight YLW to YYC
YYC Calgary Canada
Contact Airlines It may not operate on the date requested
Departure Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 10:25
MA 9
Arrival Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 12:28
None C53
WS958 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 10 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: Tuesday
Passenger Services
  • Service type: Normal passenger
  • Seats: 134
  • Freight capacity: 1.9 tons
  • Passenger classes: First Class, Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: Boeing 737-800 (Scimitar Winglets) Passenger
  • Callsign: WJA958
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Edmonton
  • Current Time in Kelowna: Sunday 2026-01-18 11:53 AM
  • Current Time in Calgary: Sunday 2026-01-18 12:53 PM

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WestJet Flight WS958 FAQs

What is the scheduled flight duration for WestJet WS958 flight?

On average, nonstop flight takes 1 hour(s) 10 minutes, with the flight distance of 403 km (250 miles).

What type of aircraft is used for the WestJet WS958 flight?

All WestJet WS958 flights are operated using Boeing 737-800 (Scimitar Winglets) Passenger aircraft.

How many WestJet WS958 flights are operated a week?

1 flights per week. The Flight WestJet WS958 is operated on Tuesday.