WestJet WS747 Flight Status Today

Domestic flight WestJet WS747 takes off from Sioux Lookout (YXL) Canada to Sandy Lake (ZSJ) Canada. It's operated by WestJet Airlines. The plane leaves Sioux Lookout Airport at 16:40 America/Winnipeg. The flight is expected to land at Sandy Lake Airport at 17:50 America/Winnipeg. The flight will last about 1 hours 30 minutes.

WS747 - WJA747 WestJet Airlines (WS)
YXL Sioux Lookout Canada
Flight YXL to ZSJ
ZSJ Sandy Lake Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 24-July-2018
Departure Sioux Lookout Airport
IATA: YXLICAO: CYXL
Scheduled 16:40
None None
Arrival Sandy Lake Airport
IATA: ZSJICAO: CZSJ
Scheduled 17:50
None None
WS747 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 30 minutes
  • Flight Distance: 337 kms / 210 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/Winnipeg
  • Arrival Timezone: America/Winnipeg
  • Current Time in Sioux Lookout: Thursday 2026-01-01 17:17 PM
  • Current Time in Sandy Lake: Thursday 2026-01-01 17:17 PM

Flight routes similar to WestJet WS747

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WestJet Flight WS747 FAQs

What is the scheduled flight duration for WestJet WS747 flight?

On average, nonstop flight takes 1 hour(s) 30 minutes, with the flight distance of 337 km (210 miles).