WestJet WS7449 Flight Status Today

Domestic flight WestJet WS7449 takes off from Atlanta (ATL) United States to Seattle (SEA) United States. It's operated by WestJet Airlines. The plane leaves Hartsfield-Jackson Atlanta International Airport at 07:25 America/New_York. The flight is expected to land at Seattle International Airport at 10:01 America/Los_Angeles. The flight will last about 5 hours 30 minutes.

WS7449 - WJA7449 WestJet Airlines (WS)
ATL Atlanta United States
Flight ATL to SEA
SEA Seattle United States
Contact Airlines It may not operate on the date requested
Departure Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 07:25
S T8
Arrival Seattle International Airport
IATA: SEAICAO: KSEA
Scheduled 10:01
None B3
WS7449 Detail
  • Type: Domestic Flight
  • Flight Duration: 5 hours 30 minutes
  • Flight Distance: 3509 kms / 2181 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 3 tons
  • Passenger classes: Economy
More Detail
  • Aircraft: Boeing 737-900 Passenger (Scimitar Winglets)
  • Callsign: WJA7449
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Los_Angeles
  • Current Time in Atlanta: Thursday 2026-04-09 04:56 AM
  • Current Time in Seattle: Thursday 2026-04-09 01:56 AM

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WestJet Flight WS7449 FAQs

What is the scheduled flight duration for WestJet WS7449 flight?

On average, nonstop flight takes 5 hour(s) 30 minutes, with the flight distance of 3509 km (2181 miles).

What type of aircraft is used for the WestJet WS7449 flight?

All WestJet WS7449 flights are operated using Boeing 737-900 Passenger (Scimitar Winglets) aircraft.

How many WestJet WS7449 flights are operated a week?

6 flights per week. The Flight WestJet WS7449 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday.