WestJet WS480 Flight Status Today

Domestic flight WestJet WS480 takes off from Kelowna (YLW) Canada to Calgary (YYC) Canada. It's operated by WestJet Airlines. The plane leaves Kelowna International Airport at 17:45 America/Vancouver. The flight is expected to land at Calgary International Airport at 19:43 America/Edmonton. The flight will last about 1 hours 15 minutes.

WS480 - WJA480 WestJet Airlines (WS)
YLW Kelowna Canada
Flight YLW to YYC
YYC Calgary Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 23-August-2021
Departure Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 17:45
None 7
Arrival Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 19:43
None C70
WS480 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 15 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 136
  • Freight capacity: 1.9 tons
  • Passenger classes: Economy, Shuttle
More Detail
  • Aircraft: Boeing 737-800 (Scimitar Winglets) Passenger
  • Callsign: WJA480
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Edmonton
  • Current Time in Kelowna: Sunday 2026-01-18 10:10 AM
  • Current Time in Calgary: Sunday 2026-01-18 11:10 AM

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WestJet Flight WS480 FAQs

What is the scheduled flight duration for WestJet WS480 flight?

On average, nonstop flight takes 1 hour(s) 15 minutes, with the flight distance of 403 km (250 miles).

What type of aircraft is used for the WestJet WS480 flight?

All WestJet WS480 flights are operated using Boeing 737-800 (Scimitar Winglets) Passenger aircraft.