WestJet WS4763 Flight Status Today

Domestic flight WestJet WS4763 takes off from Kelowna (YLW) Canada to Calgary (YYC) Canada. It's operated by WestJet Airlines. The plane leaves Kelowna International Airport at 16:00 America/Vancouver. The flight is expected to land at Calgary International Airport at 18:09 America/Edmonton. The flight will last about 1 hours 9 minutes.

WS4763 - WJA4763 WestJet Airlines (WS)
YLW Kelowna Canada
Flight YLW to YYC
YYC Calgary Canada
Contact Airlines It may not operate on the date requested
Departure Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 16:00
None None
Arrival Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 18:09
None A4
WS4763 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 9 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: Saturday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: De Havilland (Bombardier) DHC-8-400 Dash 8Q
  • Callsign: None
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Edmonton
  • Current Time in Kelowna: Saturday 2026-02-07 17:28 PM
  • Current Time in Calgary: Saturday 2026-02-07 18:28 PM

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WestJet Flight WS4763 FAQs

What is the scheduled flight duration for WestJet WS4763 flight?

On average, nonstop flight takes 1 hour(s) 9 minutes, with the flight distance of 403 km (250 miles).

What type of aircraft is used for the WestJet WS4763 flight?

All WestJet WS4763 flights are operated using De Havilland (Bombardier) DHC-8-400 Dash 8Q aircraft.

How many WestJet WS4763 flights are operated a week?

1 flights per week. The Flight WestJet WS4763 is operated on Saturday.