WestJet WS4762 Flight Status Today

Domestic flight WestJet WS4762 takes off from Calgary (YYC) Canada to Kelowna (YLW) Canada. It's operated by WestJet Airlines. The plane leaves Calgary International Airport at 15:00 America/Edmonton. The flight is expected to land at Kelowna International Airport at 15:14 America/Vancouver. The flight will last about 1 hours 20 minutes.

WS4762 - WJA4762 WestJet Airlines (WS)
YYC Calgary Canada
Flight YYC to YLW
YLW Kelowna Canada
Contact Airlines It may not operate on the date requested
Departure Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 15:00
None A5
Arrival Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 15:14
None 7
WS4762 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 20 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: De Havilland (Bombardier) DHC-8-400 Dash 8Q
  • Callsign: F-CYXD3
  • Departure Timezone: America/Edmonton
  • Arrival Timezone: America/Vancouver
  • Current Time in Calgary: Thursday 2026-04-09 18:23 PM
  • Current Time in Kelowna: Thursday 2026-04-09 17:23 PM

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WestJet Flight WS4762 FAQs

What is the scheduled flight duration for WestJet WS4762 flight?

On average, nonstop flight takes 1 hour(s) 20 minutes, with the flight distance of 403 km (250 miles).

What type of aircraft is used for the WestJet WS4762 flight?

All WestJet WS4762 flights are operated using De Havilland (Bombardier) DHC-8-400 Dash 8Q aircraft.

How many WestJet WS4762 flights are operated a week?

1 flights per week. The Flight WestJet WS4762 is operated on Friday.