WestJet WS4758 Flight Status Today

Domestic flight WestJet WS4758 takes off from Kelowna (YLW) Canada to Calgary (YYC) Canada. It's operated by WestJet Airlines. The plane leaves Kelowna International Airport at 10:00 America/Vancouver. The flight is expected to land at Calgary International Airport at 12:10 America/Edmonton. The flight will last about 1 hours 2 minutes.

WS4758 - WJA4758 WestJet Airlines (WS)
YLW Kelowna Canada
Flight YLW to YYC
YYC Calgary Canada
Contact Airlines It may not operate on the date requested
Departure Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 10:00
MA 7
Arrival Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 12:10
None A23
WS4758 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 2 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: De Havilland (Bombardier) DHC-8-400 Dash 8Q
  • Callsign: F-CYYC7
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Edmonton
  • Current Time in Kelowna: Monday 2025-12-29 01:34 AM
  • Current Time in Calgary: Monday 2025-12-29 02:34 AM

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WestJet Flight WS4758 FAQs

What is the scheduled flight duration for WestJet WS4758 flight?

On average, nonstop flight takes 1 hour(s) 2 minutes, with the flight distance of 403 km (250 miles).

What type of aircraft is used for the WestJet WS4758 flight?

All WestJet WS4758 flights are operated using De Havilland (Bombardier) DHC-8-400 Dash 8Q aircraft.

How many WestJet WS4758 flights are operated a week?

1 flights per week. The Flight WestJet WS4758 is operated on Friday.