WestJet WS4675 Flight Status Today

Domestic flight WestJet WS4675 takes off from Calgary (YYC) Canada to Kelowna (YLW) Canada. It's operated by WestJet Airlines. The plane leaves Calgary International Airport at 10:15 America/Edmonton. The flight is expected to land at Kelowna International Airport at 10:34 America/Vancouver. The flight will last about 45 minutes.

WS4675 - WJA4675 WestJet Airlines (WS)
YYC Calgary Canada
Flight YYC to YLW
YLW Kelowna Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 23-March-2021
Departure Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 10:15
Arrival Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 10:34
WS4675 Detail
  • Type: Domestic Flight
  • Flight Duration: 45 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft:
  • Callsign: None
  • Departure Timezone: America/Edmonton
  • Arrival Timezone: America/Vancouver
  • Current Time in Calgary: Sunday 2026-01-18 11:11 AM
  • Current Time in Kelowna: Sunday 2026-01-18 10:11 AM

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WestJet Flight WS4675 FAQs

What is the scheduled flight duration for WestJet WS4675 flight?

On average, nonstop flight takes 45 minutes, with the flight distance of 403 km (250 miles).