WestJet WS4565 Flight Status Today

Domestic flight WestJet WS4565 takes off from Calgary (YYC) Canada to Kelowna (YLW) Canada. It's operated by WestJet Airlines. The plane leaves Calgary International Airport at 18:45 America/Edmonton. The flight is expected to land at Kelowna International Airport at 18:47 America/Vancouver. The flight will last about 1 hours 2 minutes.

WS4565 - WJA4565 WestJet Airlines (WS)
YYC Calgary Canada
Flight YYC to YLW
YLW Kelowna Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 26-July-2021
Departure Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 18:45
None D83
Arrival Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 18:47
None 7
WS4565 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 2 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-800 (Scimitar Winglets) Passenger
  • Callsign: None
  • Departure Timezone: America/Edmonton
  • Arrival Timezone: America/Vancouver
  • Current Time in Calgary: Wednesday 2026-04-29 23:55 PM
  • Current Time in Kelowna: Wednesday 2026-04-29 22:55 PM

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WestJet Flight WS4565 FAQs

What is the scheduled flight duration for WestJet WS4565 flight?

On average, nonstop flight takes 1 hour(s) 2 minutes, with the flight distance of 403 km (250 miles).

What type of aircraft is used for the WestJet WS4565 flight?

All WestJet WS4565 flights are operated using Boeing 737-800 (Scimitar Winglets) Passenger aircraft.