WestJet WS4475 Flight Status Today

Domestic flight WestJet WS4475 takes off from Calgary (YYC) Canada to Kelowna (YLW) Canada. It's operated by WestJet Airlines. The plane leaves Calgary International Airport at 10:15 America/Edmonton. The flight is expected to land at Kelowna International Airport at 10:15 America/Vancouver. The flight will last about 1 hours 30 minutes.

WS4475 - WJA4475 WestJet Airlines (WS)
YYC Calgary Canada
Flight YYC to YLW
YLW Kelowna Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 05-April-2021
Departure Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 10:15
None 20
Arrival Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 10:15
3 C29A
WS4475 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 30 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-800 Passenger
  • Callsign: WJA4475
  • Departure Timezone: America/Edmonton
  • Arrival Timezone: America/Vancouver
  • Current Time in Calgary: Sunday 2026-01-18 11:13 AM
  • Current Time in Kelowna: Sunday 2026-01-18 10:13 AM

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WestJet Flight WS4475 FAQs

What is the scheduled flight duration for WestJet WS4475 flight?

On average, nonstop flight takes 1 hour(s) 30 minutes, with the flight distance of 403 km (250 miles).

What type of aircraft is used for the WestJet WS4475 flight?

All WestJet WS4475 flights are operated using Boeing 737-800 Passenger aircraft.

Which terminal the flight WestJet WS4475 is arriving at?

Flight WestJet WS4475 arrives in Kelowna International Airport at Terminal 3.