WestJet WS4403 Flight Status Today

Domestic flight WestJet WS4403 takes off from Kelowna (YLW) Canada to Calgary (YYC) Canada. It's operated by WestJet Airlines. The plane leaves Kelowna International Airport at 15:45 America/Vancouver. The flight is expected to land at Calgary International Airport at 18:21 America/Edmonton. The flight will last about 1 hours 36 minutes.

WS4403 - WJA4403 WestJet Airlines (WS)
YLW Kelowna Canada
Flight YLW to YYC
YYC Calgary Canada
Contact Airlines It may not operate on the date requested
Departure Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 15:45
None 7
Arrival Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 18:21
None A24
WS4403 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 36 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: Monday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-700 (winglets) Passenger/BBJ1
  • Callsign: F-CYYC6
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Edmonton
  • Current Time in Kelowna: Saturday 2026-02-07 15:40 PM
  • Current Time in Calgary: Saturday 2026-02-07 16:40 PM

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WestJet Flight WS4403 FAQs

What is the scheduled flight duration for WestJet WS4403 flight?

On average, nonstop flight takes 1 hour(s) 36 minutes, with the flight distance of 403 km (250 miles).

What type of aircraft is used for the WestJet WS4403 flight?

All WestJet WS4403 flights are operated using Boeing 737-700 (winglets) Passenger/BBJ1 aircraft.

How many WestJet WS4403 flights are operated a week?

1 flights per week. The Flight WestJet WS4403 is operated on Monday.