WestJet WS3628 Flight Status Today

Domestic flight WestJet WS3628 takes off from Kamloops (YKA) Canada to Calgary (YYC) Canada. It's operated by WestJet Airlines. The plane leaves Kamloops Airport at 05:20 America/Vancouver. The flight is expected to land at Calgary International Airport at 07:40 America/Edmonton. The flight will last about 1 hours 37 minutes.

WS3628 - WJA3628 WestJet Airlines (WS)
YKA Kamloops Canada
Flight YKA to YYC
YYC Calgary Canada
Contact Airlines It may not operate on the date requested
Departure Kamloops Airport
IATA: YKAICAO: CYKA
Scheduled 05:20
MA 2
Arrival Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 07:40
None A3
WS3628 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 37 minutes
  • Flight Distance: 455 kms / 282 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 78
  • Freight capacity: 1.6 tons
  • Passenger classes: First Class, Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: De Havilland (Bombardier) DHC-8-400 Dash 8Q
  • Callsign: F-KPDX4
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Edmonton
  • Current Time in Kamloops: Monday 2026-01-19 01:54 AM
  • Current Time in Calgary: Monday 2026-01-19 02:54 AM

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WestJet Flight WS3628 FAQs

What is the scheduled flight duration for WestJet WS3628 flight?

On average, nonstop flight takes 1 hour(s) 37 minutes, with the flight distance of 455 km (282 miles).

What type of aircraft is used for the WestJet WS3628 flight?

All WestJet WS3628 flights are operated using De Havilland (Bombardier) DHC-8-400 Dash 8Q aircraft.

How many WestJet WS3628 flights are operated a week?

1 flights per week. The Flight WestJet WS3628 is operated on Sunday.