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WestJet WS2275 Flight Status Today
International flight WestJet WS2275 takes off from Belize City (BZE) Belize to Calgary (YYC) Canada. It's operated by WestJet Airlines. The plane leaves Philip S.W. Goldson International Airport at 15:00 09 February 2026 America/Belize. The flight is expected to land at Calgary International Airport at 20:26 09 February 2026 America/Edmonton. The flight will last about 6 hours 26 minutes.
Current status of WS2275 is Scheduled On time Estimated Depart in 5 hours, 59 minutes
WS2275 - WJA2275
WestJet Airlines (WS)
BZE
Belize City Belize
YYC
Calgary Canada
Scheduled On time
Estimated Depart in 5 hours, 59 minutes
Scheduled
15:00 09 February 2026
Estimated
15:00 09 February 2026
MA
1
Scheduled
20:26 09 February 2026
Estimated
20:26 09 February 2026
None
D78
WS2275 Detail
- Type: International Flight
- Flight Duration: 6 hours 26 minutes
- Flight Distance: 4366 kms / 2713 miles
Airline
- WestJet Airlines
- IATA: WS
- ICAO: WJA
- Operating Days:
Passenger Services
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
More Detail
- Aircraft: Boeing 737MAX 8 Passenger
- Callsign: WJA2275
- Departure Timezone: America/Belize
- Arrival Timezone: America/Edmonton
- Current Time in Belize City: Monday 2026-02-09 09:01 AM
- Current Time in Calgary: Monday 2026-02-09 08:01 AM
WestJet Flight WS2275 FAQs
What is the scheduled flight duration for WestJet WS2275 flight?
On average, nonstop flight takes 6 hour(s) 26 minutes, with the flight distance of 4366 km (2713 miles).
What is the current status of WestJet WS2275 flight?
The current status of flight WestJet WS2275 is Scheduled On time.
What type of aircraft is used for the WestJet WS2275 flight?
All WestJet WS2275 flights are operated using Boeing 737MAX 8 Passenger aircraft.