WestJet WS2275 Flight Status Today

International flight WestJet WS2275 takes off from Belize City (BZE) Belize to Calgary (YYC) Canada. It's operated by WestJet Airlines. The plane leaves Philip S.W. Goldson International Airport at 15:00 America/Belize. The flight is expected to land at Calgary International Airport at 20:27 America/Edmonton. The flight will last about 6 hours 27 minutes.

WS2275 - WJA2275 WestJet Airlines (WS)
BZE Belize City Belize
Flight BZE to YYC
YYC Calgary Canada
Contact Airlines It may not operate on the date requested
Departure Philip S.W. Goldson International Airport
IATA: BZEICAO: MZBZ
Scheduled 15:00
MA 1
Arrival Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 20:27
None D75
WS2275 Detail
  • Type: International Flight
  • Flight Duration: 6 hours 27 minutes
  • Flight Distance: 4366 kms / 2713 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days:
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: WJA2275
  • Departure Timezone: America/Belize
  • Arrival Timezone: America/Edmonton
  • Current Time in Belize City: Tuesday 2026-01-20 03:54 AM
  • Current Time in Calgary: Tuesday 2026-01-20 02:54 AM

Flight routes similar to WestJet WS2275

Airline Flight no Departure Arrival
WestJet WS2217
WestJet 		20/01/2026
14:00 		6 hours 25 minutes
20:25
WestJet WS4217
WestJet 		20/01/2026
16:00 		6 hours 19 minutes
22:19

WestJet Flight WS2275 FAQs

What is the scheduled flight duration for WestJet WS2275 flight?

On average, nonstop flight takes 6 hour(s) 27 minutes, with the flight distance of 4366 km (2713 miles).

What type of aircraft is used for the WestJet WS2275 flight?

All WestJet WS2275 flights are operated using Boeing 737MAX 8 Passenger aircraft.