WestJet WS2045 Flight Status Today

Domestic flight WestJet WS2045 takes off from Kelowna (YLW) Canada to Calgary (YYC) Canada. It's operated by WestJet Airlines. The plane leaves Kelowna International Airport at 19:53 America/Vancouver. The flight is expected to land at Calgary International Airport at None America/Edmonton. The flight will last about 1 hours 6 minutes.

WS2045 - WJA2045 WestJet Airlines (WS)
YLW Kelowna Canada
Flight YLW to YYC
YYC Calgary Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 19:53
None None
Arrival Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled None
None None
WS2045 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 6 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-7CT
  • Callsign: NCB2045
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Edmonton
  • Current Time in Kelowna: Saturday 2026-02-07 17:28 PM
  • Current Time in Calgary: Saturday 2026-02-07 18:28 PM

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WestJet Flight WS2045 FAQs

What is the scheduled flight duration for WestJet WS2045 flight?

On average, nonstop flight takes 1 hour(s) 6 minutes, with the flight distance of 403 km (250 miles).

What type of aircraft is used for the WestJet WS2045 flight?

All WestJet WS2045 flights are operated using Boeing 737-7CT aircraft.