WestJet WS1878 Flight Status Today

International flight WestJet WS1878 takes off from Calgary (YYC) Canada to Honolulu (HNL) United States. It's operated by WestJet Airlines. The plane leaves Calgary International Airport at 18:00 America/Edmonton. The flight is expected to land at Daniel K. Inouye International Airport at 21:54 Pacific/Honolulu. The flight will last about 4 hours 8 minutes.

WS1878 - WJA1878 WestJet Airlines (WS)
YYC Calgary Canada
Flight YYC to HNL
HNL Honolulu United States
Contact Airlines It may not operate on the date requested
Departure Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 18:00
None E87
Arrival Daniel K. Inouye International Airport
IATA: HNLICAO: PHNL
Scheduled 21:54
2 None
WS1878 Detail
  • Type: International Flight
  • Flight Duration: 4 hours 8 minutes
  • Flight Distance: 5031 kms / 3126 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days:
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 787-9 Dreamliner
  • Callsign: WJ1878
  • Departure Timezone: America/Edmonton
  • Arrival Timezone: Pacific/Honolulu
  • Current Time in Calgary: Thursday 2026-01-01 15:08 PM
  • Current Time in Honolulu: Thursday 2026-01-01 12:08 PM

Flight routes similar to WestJet WS1878

Airline Flight no Departure Arrival
WestJet WS1876
WestJet 		01/01/2026
18:00 		6 hours 54 minutes
21:54
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Air Canada AC529
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Bonza Air AB2
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None

WestJet Flight WS1878 FAQs

What is the scheduled flight duration for WestJet WS1878 flight?

On average, nonstop flight takes 4 hour(s) 8 minutes, with the flight distance of 5031 km (3126 miles).

What type of aircraft is used for the WestJet WS1878 flight?

All WestJet WS1878 flights are operated using Boeing 787-9 Dreamliner aircraft.

Which terminal the flight WestJet WS1878 is arriving at?

Flight WestJet WS1878 arrives in Daniel K. Inouye International Airport at Terminal 2.