WestJet WS1843 Flight Status Today

International flight WestJet WS1843 takes off from Phoenix (PHX) United States to Kelowna (YLW) Canada. It's operated by WestJet Airlines. The plane leaves Phoenix Sky Harbor International Airport at 12:40 America/Phoenix. The flight is expected to land at Kelowna International Airport at 15:00 America/Vancouver. The flight will last about 2 hours 0 minutes.

WS1843 - WJA1843 WestJet Airlines (WS)
PHX Phoenix United States
Flight PHX to YLW
YLW Kelowna Canada
Contact Airlines It may not operate on the date requested
Departure Phoenix Sky Harbor International Airport
IATA: PHXICAO: KPHX
Scheduled 12:40
4 B27
Arrival Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 15:00
None 4
WS1843 Detail
  • Type: International Flight
  • Flight Duration: 2 hours 0 minutes
  • Flight Distance: 1932 kms / 1201 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days:
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-8CT
  • Callsign: WJA1843
  • Departure Timezone: America/Phoenix
  • Arrival Timezone: America/Vancouver
  • Current Time in Phoenix: Sunday 2026-01-18 14:21 PM
  • Current Time in Kelowna: Sunday 2026-01-18 13:21 PM

Flight routes similar to WestJet WS1843

Airline Flight no Departure Arrival
WestJet WS1323
WestJet 		18/01/2026
15:15 		3 hours 12 minutes
18:27

WestJet Flight WS1843 FAQs

What is the scheduled flight duration for WestJet WS1843 flight?

On average, nonstop flight takes 2 hour(s) 0 minutes, with the flight distance of 1932 km (1201 miles).

What type of aircraft is used for the WestJet WS1843 flight?

All WestJet WS1843 flights are operated using Boeing 737-8CT aircraft.