WestJet WS1473 Flight Status Today

International flight WestJet WS1473 takes off from Palm Springs (PSP) United States to Calgary (YYC) Canada. It's operated by WestJet Airlines. The plane leaves Palm Springs International Airport at 16:05 America/Los_Angeles. The flight is expected to land at Calgary International Airport at 20:08 America/Edmonton. The flight will last about 3 hours 3 minutes.

WS1473 - WJA1473 WestJet Airlines (WS)
PSP Palm Springs United States
Flight PSP to YYC
YYC Calgary Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 24-April-2017
Departure Palm Springs International Airport
IATA: PSPICAO: KPSP
Scheduled 16:05
Arrival Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 20:08
WS1473 Detail
  • Type: International Flight
  • Flight Duration: 3 hours 3 minutes
  • Flight Distance: 1933 kms / 1201 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 136
  • Freight capacity: 1.9 tons
  • Passenger classes: Economy, Shuttle
More Detail
  • Aircraft: 73W
  • Callsign: WJA1473
  • Departure Timezone: America/Los_Angeles
  • Arrival Timezone: America/Edmonton
  • Current Time in Palm Springs: Monday 2025-12-29 06:53 AM
  • Current Time in Calgary: Monday 2025-12-29 07:53 AM

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WestJet Flight WS1473 FAQs

What is the scheduled flight duration for WestJet WS1473 flight?

On average, nonstop flight takes 3 hour(s) 3 minutes, with the flight distance of 1933 km (1201 miles).

What type of aircraft is used for the WestJet WS1473 flight?

All WestJet WS1473 flights are operated using 73W aircraft.