WestJet WS1470 Flight Status Today

International flight WestJet WS1470 takes off from Calgary (YYC) Canada to Palm Springs (PSP) United States. It's operated by WestJet Airlines. The plane leaves Calgary International Airport at 12:30 America/Edmonton. The flight is expected to land at Palm Springs International Airport at 14:34 America/Los_Angeles. The flight will last about 3 hours 4 minutes.

WS1470 - WJA1470 WestJet Airlines (WS)
YYC Calgary Canada
Flight YYC to PSP
PSP Palm Springs United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 26-April-2019
Departure Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 12:30
N/A
Arrival Palm Springs International Airport
IATA: PSPICAO: KPSP
Scheduled 14:34
N/A
WS1470 Detail
  • Type: International Flight
  • Flight Duration: 3 hours 4 minutes
  • Flight Distance: 1933 kms / 1201 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 113
  • Freight capacity: 1.2 tons
  • Passenger classes: First Class, Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: Boeing 737-600 Passenger
  • Callsign: WJA1470
  • Departure Timezone: America/Edmonton
  • Arrival Timezone: America/Los_Angeles
  • Current Time in Calgary: Monday 2025-12-29 15:36 PM
  • Current Time in Palm Springs: Monday 2025-12-29 14:36 PM

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WestJet Flight WS1470 FAQs

What is the scheduled flight duration for WestJet WS1470 flight?

On average, nonstop flight takes 3 hour(s) 4 minutes, with the flight distance of 1933 km (1201 miles).

What type of aircraft is used for the WestJet WS1470 flight?

All WestJet WS1470 flights are operated using Boeing 737-600 Passenger aircraft.

Which terminal the flight WestJet WS1470 is arriving at?

Flight WestJet WS1470 arrives in Palm Springs International Airport at Terminal N/A.