WestJet WS1452 Flight Status Today

International flight WestJet WS1452 takes off from Calgary (YYC) Canada to Palm Springs (PSP) United States. It's operated by WestJet Airlines. The plane leaves Calgary International Airport at 08:00 America/Edmonton. The flight is expected to land at Palm Springs International Airport at 10:03 America/Los_Angeles. The flight will last about 3 hours 4 minutes.

WS1452 - WJA1452 WestJet Airlines (WS)
YYC Calgary Canada
Flight YYC to PSP
PSP Palm Springs United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 16-May-2019
Departure Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 08:00
None None
Arrival Palm Springs International Airport
IATA: PSPICAO: KPSP
Scheduled 10:03
None None
WS1452 Detail
  • Type: International Flight
  • Flight Duration: 3 hours 4 minutes
  • Flight Distance: 1933 kms / 1201 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/Edmonton
  • Arrival Timezone: America/Los_Angeles
  • Current Time in Calgary: Monday 2026-01-19 11:32 AM
  • Current Time in Palm Springs: Monday 2026-01-19 10:32 AM

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WestJet Flight WS1452 FAQs

What is the scheduled flight duration for WestJet WS1452 flight?

On average, nonstop flight takes 3 hour(s) 4 minutes, with the flight distance of 1933 km (1201 miles).