WestJet WS1014 Flight Status Today

International flight WestJet WS1014 takes off from Calgary (YYC) Canada to Palm Springs (PSP) United States. It's operated by WestJet Airlines. The plane leaves Calgary International Airport at 08:30 America/Edmonton. The flight is expected to land at Palm Springs International Airport at 10:34 America/Los_Angeles. The flight will last about 3 hours 4 minutes.

WS1014 - WJA1014 WestJet Airlines (WS)
YYC Calgary Canada
Flight YYC to PSP
PSP Palm Springs United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 08-April-2019
Departure Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 08:30
None E91
Arrival Palm Springs International Airport
IATA: PSPICAO: KPSP
Scheduled 10:34
None 4
WS1014 Detail
  • Type: International Flight
  • Flight Duration: 3 hours 4 minutes
  • Flight Distance: 1933 kms / 1201 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 134
  • Freight capacity: 1.9 tons
  • Passenger classes: First Class, Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: Boeing 737 Passenger
  • Callsign: WJA1014
  • Departure Timezone: America/Edmonton
  • Arrival Timezone: America/Los_Angeles
  • Current Time in Calgary: Monday 2026-01-19 05:51 AM
  • Current Time in Palm Springs: Monday 2026-01-19 04:51 AM

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WestJet Flight WS1014 FAQs

What is the scheduled flight duration for WestJet WS1014 flight?

On average, nonstop flight takes 3 hour(s) 4 minutes, with the flight distance of 1933 km (1201 miles).

What type of aircraft is used for the WestJet WS1014 flight?

All WestJet WS1014 flights are operated using Boeing 737 Passenger aircraft.