Swift Air WQ9878 Flight Status Today

Domestic flight Swift Air WQ9878 takes off from Indianapolis (IND) United States to Columbus (CMH) United States. It's operated by Swift Air. The plane leaves Indianapolis International Airport at 20:10 America/Indiana/Indianapolis. The flight is expected to land at John Glenn Columbus International Airport at 21:27 America/New_York. The flight will last about 2 hours 43 minutes.

WQ9878 - SWQ9878 Swift Air (WQ)
IND Indianapolis United States
Flight IND to CMH
CMH Columbus United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 03-April-2021
Departure Indianapolis International Airport
IATA: INDICAO: KIND
Scheduled 20:10
None None
Arrival John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled 21:27
None None
WQ9878 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 43 minutes
  • Flight Distance: 293 kms / 182 miles
Airline
  • Swift Air
  • IATA: WQ
  • ICAO: SWQ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-400 Passenger
  • Callsign: SWQ9878
  • Departure Timezone: America/Indiana/Indianapolis
  • Arrival Timezone: America/New_York
  • Current Time in Indianapolis: Monday 2026-03-02 00:24 AM
  • Current Time in Columbus: Monday 2026-03-02 00:24 AM

Flight routes similar to Swift Air WQ9878

Airline Flight no Departure Arrival
Southwest Airlines WN8806
Southwest Airlines 		02/03/2026
10:10 		60 minutes
11:10
American Airlines AA9942
American Airlines 		02/03/2026
12:50 		1 hours 10 minutes
14:00

Swift Air Flight WQ9878 FAQs

What is the scheduled flight duration for Swift Air WQ9878 flight?

On average, nonstop flight takes 2 hour(s) 43 minutes, with the flight distance of 293 km (182 miles).

What type of aircraft is used for the Swift Air WQ9878 flight?

All Swift Air WQ9878 flights are operated using Boeing 737-400 Passenger aircraft.