Swift Air WQ9849 Flight Status Today

Domestic flight Swift Air WQ9849 takes off from Oklahoma City (OKC) United States to Houston (HOU) United States. It's operated by Swift Air. The plane leaves Will Rogers World Airport at 02:20 America/Chicago. The flight is expected to land at William P. Hobby Airport at None America/Chicago. The flight will last about 1 hours 4 minutes.

WQ9849 - SWQ9849 Swift Air (WQ)
OKC Oklahoma City United States
Flight OKC to HOU
HOU Houston United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Will Rogers World Airport
IATA: OKCICAO: KOKC
Scheduled 02:20
None None
Arrival William P. Hobby Airport
IATA: HOUICAO: KHOU
Scheduled None
None None
WQ9849 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 4 minutes
  • Flight Distance: 673 kms / 418 miles
Airline
  • Swift Air
  • IATA: WQ
  • ICAO: SWQ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-4Q8
  • Callsign: SWQ9849
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Chicago
  • Current Time in Oklahoma City: Wednesday 2026-01-21 21:45 PM
  • Current Time in Houston: Wednesday 2026-01-21 21:45 PM

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Swift Air Flight WQ9849 FAQs

What is the scheduled flight duration for Swift Air WQ9849 flight?

On average, nonstop flight takes 1 hour(s) 4 minutes, with the flight distance of 673 km (418 miles).

What type of aircraft is used for the Swift Air WQ9849 flight?

All Swift Air WQ9849 flights are operated using Boeing 737-4Q8 aircraft.