Swift Air WQ9474 Flight Status Today

Domestic flight Swift Air WQ9474 takes off from Farmingdale (FRG) United States to Columbus (CMH) United States. It's operated by Swift Air. The plane leaves Republic Airport at 19:15 America/New_York. The flight is expected to land at John Glenn Columbus International Airport at None America/New_York. The flight will last about 1 hours 27 minutes.

WQ9474 - SWQ9474 Swift Air (WQ)
FRG Farmingdale United States
Flight FRG to CMH
CMH Columbus United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Republic Airport
IATA: FRGICAO: KFRG
Scheduled 19:15
None None
Arrival John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled None
None None
WQ9474 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 27 minutes
  • Flight Distance: 808 kms / 502 miles
Airline
  • Swift Air
  • IATA: WQ
  • ICAO: SWQ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-401
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Farmingdale: Wednesday 2026-01-21 08:51 AM
  • Current Time in Columbus: Wednesday 2026-01-21 08:51 AM

Flight routes similar to Swift Air WQ9474

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Ravn Alaska 7H9745
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02:00 		50 minutes
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Ravn Alaska 		21/01/2026
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01:30
NetJets 1I228
NetJets 		21/01/2026
14:30 		1 hours 2 minutes
15:56

Swift Air Flight WQ9474 FAQs

What is the scheduled flight duration for Swift Air WQ9474 flight?

On average, nonstop flight takes 1 hour(s) 27 minutes, with the flight distance of 808 km (502 miles).

What type of aircraft is used for the Swift Air WQ9474 flight?

All Swift Air WQ9474 flights are operated using Boeing 737-401 aircraft.