Swift Air WQ9453 Flight Status Today

Domestic flight Swift Air WQ9453 takes off from Chicago (ORD) United States to Belgrade (BZN) United States. It's operated by Swift Air. The plane leaves O'Hare International Airport at 00:49 America/Chicago. The flight is expected to land at Bozeman Yellowstone International Airport at None America/Denver. The flight will last about 2 hours 55 minutes.

WQ9453 - SWQ9453 Swift Air (WQ)
ORD Chicago United States
Flight ORD to BZN
BZN Belgrade United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure O'Hare International Airport
IATA: ORDICAO: KORD
Scheduled 00:49
None None
Arrival Bozeman Yellowstone International Airport
IATA: BZNICAO: KBZN
Scheduled None
None None
WQ9453 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 55 minutes
  • Flight Distance: 1909 kms / 1186 miles
Airline
  • Swift Air
  • IATA: WQ
  • ICAO: SWQ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-8Q8
  • Callsign: SWQ9453
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Denver
  • Current Time in Chicago: Wednesday 2025-12-31 07:49 AM
  • Current Time in Belgrade: Wednesday 2025-12-31 06:49 AM

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Swift Air Flight WQ9453 FAQs

What is the scheduled flight duration for Swift Air WQ9453 flight?

On average, nonstop flight takes 2 hour(s) 55 minutes, with the flight distance of 1909 km (1186 miles).

What type of aircraft is used for the Swift Air WQ9453 flight?

All Swift Air WQ9453 flights are operated using Boeing 737-8Q8 aircraft.