Swift Air WQ4008 Flight Status Today

Domestic flight Swift Air WQ4008 takes off from Cincinnati (CVG) United States to Oklahoma City (OKC) United States. It's operated by Swift Air. The plane leaves Cincinnati/Northern Kentucky Airport at 22:30 America/New_York. The flight is expected to land at Will Rogers World Airport at 00:23 America/Chicago. The flight will last about 1 hours 41 minutes.

WQ4008 - SWQ4008 Swift Air (WQ)
CVG Cincinnati United States
Flight CVG to OKC
OKC Oklahoma City United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 10-December-2020
Departure Cincinnati/Northern Kentucky Airport
IATA: CVGICAO: KCVG
Scheduled 22:30
None None
Arrival Will Rogers World Airport
IATA: OKCICAO: KOKC
Scheduled 00:23
None None
WQ4008 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 41 minutes
  • Flight Distance: 1216 kms / 756 miles
Airline
  • Swift Air
  • IATA: WQ
  • ICAO: SWQ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-400 Passenger
  • Callsign: SWQ4008
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Chicago
  • Current Time in Cincinnati: Monday 2026-04-06 02:44 AM
  • Current Time in Oklahoma City: Monday 2026-04-06 01:44 AM

Swift Air Flight WQ4008 FAQs

What is the scheduled flight duration for Swift Air WQ4008 flight?

On average, nonstop flight takes 1 hour(s) 41 minutes, with the flight distance of 1216 km (756 miles).

What type of aircraft is used for the Swift Air WQ4008 flight?

All Swift Air WQ4008 flights are operated using Boeing 737-400 Passenger aircraft.