Swift Air WQ4007 Flight Status Today

Domestic flight Swift Air WQ4007 takes off from Oklahoma City (OKC) United States to Cincinnati (CVG) United States. It's operated by Swift Air. The plane leaves Will Rogers World Airport at 17:00 America/Chicago. The flight is expected to land at Cincinnati/Northern Kentucky Airport at 20:00 America/New_York. The flight will last about 1 hours 12 minutes.

WQ4007 - SWQ4007 Swift Air (WQ)
OKC Oklahoma City United States
Flight OKC to CVG
CVG Cincinnati United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 09-December-2020
Departure Will Rogers World Airport
IATA: OKCICAO: KOKC
Scheduled 17:00
None None
Arrival Cincinnati/Northern Kentucky Airport
IATA: CVGICAO: KCVG
Scheduled 20:00
None None
WQ4007 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 12 minutes
  • Flight Distance: 1216 kms / 756 miles
Airline
  • Swift Air
  • IATA: WQ
  • ICAO: SWQ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-400 Passenger
  • Callsign: SWQ4007
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/New_York
  • Current Time in Oklahoma City: Monday 2026-04-06 01:37 AM
  • Current Time in Cincinnati: Monday 2026-04-06 02:37 AM

Flight routes similar to Swift Air WQ4007

Airline Flight no Departure Arrival
Allegiant Air G44754
Allegiant Air 		06/04/2026
18:47 		1 hours 56 minutes
21:43

Swift Air Flight WQ4007 FAQs

What is the scheduled flight duration for Swift Air WQ4007 flight?

On average, nonstop flight takes 1 hour(s) 12 minutes, with the flight distance of 1216 km (756 miles).

What type of aircraft is used for the Swift Air WQ4007 flight?

All Swift Air WQ4007 flights are operated using Boeing 737-400 Passenger aircraft.