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Swift Air WQ3700 Flight Status Today
Domestic flight Swift Air WQ3700 takes off from Alexandria (AEX) United States to Columbus (CSG) United States. It's operated by Swift Air. The plane leaves Alexandria International Airport at 10:41 America/Chicago. The flight is expected to land at Columbus Airport at 13:01 America/New_York. The flight will last about 48 minutes.
WQ3700 - SWQ3700
Swift Air (WQ)
AEX
Alexandria United States
CSG
Columbus United States
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on 11-March-2021
WQ3700 Detail
- Type: Domestic Flight
- Flight Duration: 48 minutes
- Flight Distance: 731 kms / 454 miles
Airline
- Swift Air
- IATA: WQ
- ICAO: SWQ
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Boeing 737-3H4
- Callsign: F-KCQF1
- Departure Timezone: America/Chicago
- Arrival Timezone: America/New_York
- Current Time in Alexandria: Monday 2026-01-19 07:53 AM
- Current Time in Columbus: Monday 2026-01-19 08:53 AM
Flight routes similar to Swift Air WQ3700
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
G66150 Global Crossing Airlines |
19/01/2026 06:00 |
1 hours 1 minutes 08:10 |
Swift Air Flight WQ3700 FAQs
What is the scheduled flight duration for Swift Air WQ3700 flight?
On average, nonstop flight takes 48 minutes, with the flight distance of 731 km (454 miles).
What type of aircraft is used for the Swift Air WQ3700 flight?
All Swift Air WQ3700 flights are operated using Boeing 737-3H4 aircraft.
