Swift Air WQ2605 flight status now

WQ2605 - SWQ2605 Swift Air (WQ)
CMH Columbus United States
Flight CMH to FRG
FRG Farmingdale United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled 23:00
None None
Arrival Republic Airport
IATA: FRGICAO: KFRG
Scheduled 00:27
None None
WQ2605 Detail
  • Type: Domestic Flight
  • Flight Duration: 52 minutes
  • Flight Distance: 808 kms / 502 miles
Airline
  • Swift Air
  • IATA: WQ
  • ICAO: SWQ
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-4Q8
  • Callsign: F-KFRG1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Columbus: Wednesday 2025-11-19 23:57 PM
  • Current Time in Farmingdale: Wednesday 2025-11-19 23:57 PM

Domestic flight Swift Air WQ2605 takes off from Columbus (CMH) United States to Farmingdale (FRG) United States. It's operated by Swift Air. The plane leaves John Glenn Columbus International Airport at 23:00 America/New_York. The flight is expected to land at Republic Airport at 00:27 America/New_York. The flight will last about 52 minutes.

Similar flight route from Columbus (CMH) to Farmingdale (FRG)

Airline Flight no Departure Arrival
Ravn Alaska 7H8741
Ravn Alaska 		19/11/2025
23:00 		1 hours 52 minutes
00:36
Swift Air WQ2653
Swift Air 		19/11/2025
23:00 		1 hours 13 minutes
00:27

Frequently asked questions, answered

How long is the flight from Columbus to Farmingdale?

On average, nonstop flight takes 52 minutes, with the flight distance of 808 km (502 miles).

What type of aircraft is used for the Swift Air WQ2605 flight?

All Swift Air WQ2605 flights are operated using Boeing 737-4Q8 aircraft.