Southwest Airlines WN8808 Flight Status Today

Domestic flight Southwest Airlines WN8808 takes off from Baltimore (BWI) United States to Columbus (CMH) United States. It's operated by Southwest Airlines. The plane leaves Baltimore/Wash International Thurgood Marshall Airport at 06:00 America/New_York. The flight is expected to land at John Glenn Columbus International Airport at 07:00 America/New_York. The flight will last about 60 minutes.

WN8808 - SWA8808 Southwest Airlines (WN)
BWI Baltimore United States
Flight BWI to CMH
CMH Columbus United States
Contact Airlines It may not operate on the date requested
Departure Baltimore/Wash International Thurgood Marshall Airport
IATA: BWIICAO: KBWI
Scheduled 06:00
None A12
Arrival John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled 07:00
None None
WN8808 Detail
  • Type: Domestic Flight
  • Flight Duration: 60 minutes
  • Flight Distance: 542 kms / 336 miles
Airline
  • Southwest Airlines
  • IATA: WN
  • ICAO: SWA
  • Operating Days: Tuesday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-8H4
  • Callsign: F-MMCS3
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Baltimore: Wednesday 2026-03-04 07:28 AM
  • Current Time in Columbus: Wednesday 2026-03-04 07:28 AM

Flight routes similar to Southwest Airlines WN8808

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Southwest Airlines Flight WN8808 FAQs

What is the scheduled flight duration for Southwest Airlines WN8808 flight?

On average, nonstop flight takes 60 minutes, with the flight distance of 542 km (336 miles).

What type of aircraft is used for the Southwest Airlines WN8808 flight?

All Southwest Airlines WN8808 flights are operated using Boeing 737-8H4 aircraft.

How many Southwest Airlines WN8808 flights are operated a week?

1 flights per week. The Flight Southwest Airlines WN8808 is operated on Tuesday.